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Implicit if

22. Even number or not (2.7.2009)

/*
Program# 22
date : 25-12-2008
Even number or not
*/

#include <stdio.h>
main(){
int n,x;
printf("\nEnter a integer :");
scanf("%d",&n);
x=n%2;
if(x)
printf("\n%d : Not an Even number\n",n);
else
printf("\n%d : Even number\n",n);
}

output:
Enter a integer : 13
13 : Not an Even number

Things to note: Here the value 1 is considered as true and value 0 as false.

Syntax for implicit if

if(true)
do this;
else
do this;